8x-4-3=2(x-1)+x

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Solution for 8x-4-3=2(x-1)+x equation: 



8x-4-3=2(x-1)+x

We move all terms to the left:

8x-4-3-(2(x-1)+x)=0

We add all the numbers together, and all the variables

8x-(2(x-1)+x)-7=0



We calculate terms in parentheses: -(2(x-1)+x), so:

2(x-1)+x

We add all the numbers together, and all the variables

x+2(x-1)

We multiply parentheses

x+2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

8x-3x+2-7=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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