8x-3x(x-1)=4(x+2)

Solution for 8x-3x(x-1)=4(x+2) equation:

8x-3x(x-1)=4(x+2)

We move all terms to the left:

8x-3x(x-1)-(4(x+2))=0

We multiply parentheses

-3x^2+8x+3x-(4(x+2))=0


We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)


We add all the numbers together, and all the variables

-3x^2+11x-(4x+8)=0

We get rid of parentheses

-3x^2+11x-4x-8=0

We add all the numbers together, and all the variables

-3x^2+7x-8=0

a = -3; b = 7; c = -8;
Δ = b2-4ac
Δ = 72-4·(-3)·(-8)
Δ = -47
Delta is less than zero, so there is no solution for the equation