8x-3x(2x+7)=-19

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Solution for 8x-3x(2x+7)=-19 equation:



8x-3x(2x+7)=-19
We move all terms to the left:
8x-3x(2x+7)-(-19)=0
We add all the numbers together, and all the variables
8x-3x(2x+7)+19=0
We multiply parentheses
-6x^2+8x-21x+19=0
We add all the numbers together, and all the variables
-6x^2-13x+19=0
a = -6; b = -13; c = +19;
Δ = b2-4ac
Δ = -132-4·(-6)·19
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-25}{2*-6}=\frac{-12}{-12} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+25}{2*-6}=\frac{38}{-12} =-3+1/6 $

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