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8x-3(x2)=5(x+1)
We move all terms to the left:
8x-3(x2)-(5(x+1))=0
We add all the numbers together, and all the variables
-3x^2+8x-(5(x+1))=0
We calculate terms in parentheses: -(5(x+1)), so:We get rid of parentheses
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
-3x^2+8x-5x-5=0
We add all the numbers together, and all the variables
-3x^2+3x-5=0
a = -3; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-3)·(-5)
Δ = -51
Delta is less than zero, so there is no solution for the equation
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