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8x-3(x-1)=(x+2)
We move all terms to the left:
8x-3(x-1)-((x+2))=0
We multiply parentheses
8x-3x-((x+2))+3=0
We calculate terms in parentheses: -((x+2)), so:We add all the numbers together, and all the variables
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
5x-(x+2)+3=0
We get rid of parentheses
5x-x-2+3=0
We add all the numbers together, and all the variables
4x+1=0
We move all terms containing x to the left, all other terms to the right
4x=-1
x=-1/4
x=-1/4
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