8x-3(x+2)=2(x-3)+2(x-2)

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Solution for 8x-3(x+2)=2(x-3)+2(x-2) equation: 



8x-3(x+2)=2(x-3)+2(x-2)

We move all terms to the left:

8x-3(x+2)-(2(x-3)+2(x-2))=0

We multiply parentheses

8x-3x-(2(x-3)+2(x-2))-6=0



We calculate terms in parentheses: -(2(x-3)+2(x-2)), so:

2(x-3)+2(x-2)

We multiply parentheses

2x+2x-6-4

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

5x-(4x-10)-6=0

We get rid of parentheses

5x-4x+10-6=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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