8x-3(4-x)=6(x+1)-2

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Solution for 8x-3(4-x)=6(x+1)-2 equation:


Simplifying
8x + -3(4 + -1x) = 6(x + 1) + -2
8x + (4 * -3 + -1x * -3) = 6(x + 1) + -2
8x + (-12 + 3x) = 6(x + 1) + -2

Reorder the terms:
-12 + 8x + 3x = 6(x + 1) + -2

Combine like terms: 8x + 3x = 11x
-12 + 11x = 6(x + 1) + -2

Reorder the terms:
-12 + 11x = 6(1 + x) + -2
-12 + 11x = (1 * 6 + x * 6) + -2
-12 + 11x = (6 + 6x) + -2

Reorder the terms:
-12 + 11x = 6 + -2 + 6x

Combine like terms: 6 + -2 = 4
-12 + 11x = 4 + 6x

Solving
-12 + 11x = 4 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
-12 + 11x + -6x = 4 + 6x + -6x

Combine like terms: 11x + -6x = 5x
-12 + 5x = 4 + 6x + -6x

Combine like terms: 6x + -6x = 0
-12 + 5x = 4 + 0
-12 + 5x = 4

Add '12' to each side of the equation.
-12 + 12 + 5x = 4 + 12

Combine like terms: -12 + 12 = 0
0 + 5x = 4 + 12
5x = 4 + 12

Combine like terms: 4 + 12 = 16
5x = 16

Divide each side by '5'.
x = 3.2

Simplifying
x = 3.2

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