8x-3(2x-4)=3(x+6)

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Solution for 8x-3(2x-4)=3(x+6) equation: 



8x-3(2x-4)=3(x+6)

We move all terms to the left:

8x-3(2x-4)-(3(x+6))=0

We multiply parentheses

8x-6x-(3(x+6))+12=0



We calculate terms in parentheses: -(3(x+6)), so:

3(x+6)

We multiply parentheses

3x+18

Back to the equation:

-(3x+18)



We add all the numbers together, and all the variables

2x-(3x+18)+12=0

We get rid of parentheses

2x-3x-18+12=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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