8x-20(x+1)=-(9x+10)+2(2x-5)

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Solution for 8x-20(x+1)=-(9x+10)+2(2x-5) equation: 



8x-20(x+1)=-(9x+10)+2(2x-5)

We move all terms to the left:

8x-20(x+1)-(-(9x+10)+2(2x-5))=0

We multiply parentheses

8x-20x-(-(9x+10)+2(2x-5))-20=0



We calculate terms in parentheses: -(-(9x+10)+2(2x-5)), so:

-(9x+10)+2(2x-5)

We multiply parentheses

-(9x+10)+4x-10

We get rid of parentheses

-9x+4x-10-10

We add all the numbers together, and all the variables

-5x-20

Back to the equation:

-(-5x-20)



We add all the numbers together, and all the variables

-12x-(-5x-20)-20=0

We get rid of parentheses

-12x+5x+20-20=0

We add all the numbers together, and all the variables

-7x=0

x=0/-7

x=0

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