8x-20(x+1)=(-9+10)+2(2x-5)

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Solution for 8x-20(x+1)=(-9+10)+2(2x-5) equation: 



8x-20(x+1)=(-9+10)+2(2x-5)

We move all terms to the left:

8x-20(x+1)-((-9+10)+2(2x-5))=0

We add all the numbers together, and all the variables

8x-20(x+1)-(1+2(2x-5))=0

We multiply parentheses

8x-20x-(1+2(2x-5))-20=0



We calculate terms in parentheses: -(1+2(2x-5)), so:

1+2(2x-5)

determiningTheFunctionDomain
2(2x-5)+1

We multiply parentheses

4x-10+1

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We add all the numbers together, and all the variables

-12x-(4x-9)-20=0

We get rid of parentheses

-12x-4x+9-20=0

We add all the numbers together, and all the variables

-16x-11=0

We move all terms containing x to the left, all other terms to the right

-16x=11

x=11/-16

x=-11/16

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