8x-2(x-3)=6(x+1)+8

Solution for 8x-2(x-3)=6(x+1)+8 equation:

Simplifying
8x + -2(x + -3) = 6(x + 1) + 8

Reorder the terms:
8x + -2(-3 + x) = 6(x + 1) + 8
8x + (-3 * -2 + x * -2) = 6(x + 1) + 8
8x + (6 + -2x) = 6(x + 1) + 8

Reorder the terms:
6 + 8x + -2x = 6(x + 1) + 8

Combine like terms: 8x + -2x = 6x
6 + 6x = 6(x + 1) + 8

Reorder the terms:
6 + 6x = 6(1 + x) + 8
6 + 6x = (1 * 6 + x * 6) + 8
6 + 6x = (6 + 6x) + 8

Reorder the terms:
6 + 6x = 6 + 8 + 6x

Combine like terms: 6 + 8 = 14
6 + 6x = 14 + 6x

Add '-6x' to each side of the equation.
6 + 6x + -6x = 14 + 6x + -6x

Combine like terms: 6x + -6x = 0
6 + 0 = 14 + 6x + -6x
6 = 14 + 6x + -6x

Combine like terms: 6x + -6x = 0
6 = 14 + 0
6 = 14

Solving
6 = 14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.