8x-2(x-3)=6(x+1)+3

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Solution for 8x-2(x-3)=6(x+1)+3 equation: 



8x-2(x-3)=6(x+1)+3

We move all terms to the left:

8x-2(x-3)-(6(x+1)+3)=0

We multiply parentheses

8x-2x-(6(x+1)+3)+6=0



We calculate terms in parentheses: -(6(x+1)+3), so:

6(x+1)+3

We multiply parentheses

6x+6+3

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We add all the numbers together, and all the variables

6x-(6x+9)+6=0

We get rid of parentheses

6x-6x-9+6=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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