8x-2(x-3)=4(x+1)+4

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Solution for 8x-2(x-3)=4(x+1)+4 equation: 



8x-2(x-3)=4(x+1)+4

We move all terms to the left:

8x-2(x-3)-(4(x+1)+4)=0

We multiply parentheses

8x-2x-(4(x+1)+4)+6=0



We calculate terms in parentheses: -(4(x+1)+4), so:

4(x+1)+4

We multiply parentheses

4x+4+4

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

6x-(4x+8)+6=0

We get rid of parentheses

6x-4x-8+6=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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