8x-2(x+5)=2(x-1)+20

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Solution for 8x-2(x+5)=2(x-1)+20 equation: 



8x-2(x+5)=2(x-1)+20

We move all terms to the left:

8x-2(x+5)-(2(x-1)+20)=0

We multiply parentheses

8x-2x-(2(x-1)+20)-10=0



We calculate terms in parentheses: -(2(x-1)+20), so:

2(x-1)+20

We multiply parentheses

2x-2+20

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

6x-(2x+18)-10=0

We get rid of parentheses

6x-2x-18-10=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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