8x-2(x+1)=6x+4(x-5)

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Solution for 8x-2(x+1)=6x+4(x-5) equation: 



8x-2(x+1)=6x+4(x-5)

We move all terms to the left:

8x-2(x+1)-(6x+4(x-5))=0

We multiply parentheses

8x-2x-(6x+4(x-5))-2=0



We calculate terms in parentheses: -(6x+4(x-5)), so:

6x+4(x-5)

We multiply parentheses

6x+4x-20

We add all the numbers together, and all the variables

10x-20

Back to the equation:

-(10x-20)



We add all the numbers together, and all the variables

6x-(10x-20)-2=0

We get rid of parentheses

6x-10x+20-2=0

We add all the numbers together, and all the variables

-4x+18=0

We move all terms containing x to the left, all other terms to the right

-4x=-18

x=-18/-4

x=4+1/2

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