8x-2(X+-8)=6(X+1)+8

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Solution for 8x-2(X+-8)=6(X+1)+8 equation: 



8x-2(x+-8)=6(x+1)+8

We move all terms to the left:

8x-2(x+-8)-(6(x+1)+8)=0

We add all the numbers together, and all the variables

8x-2(x-8)-(6(x+1)+8)=0

We multiply parentheses

8x-2x-(6(x+1)+8)+16=0



We calculate terms in parentheses: -(6(x+1)+8), so:

6(x+1)+8

We multiply parentheses

6x+6+8

We add all the numbers together, and all the variables

6x+14

Back to the equation:

-(6x+14)



We add all the numbers together, and all the variables

6x-(6x+14)+16=0

We get rid of parentheses

6x-6x-14+16=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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