8x-2(3x-5)+17=7x+3(x-4)-12

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Solution for 8x-2(3x-5)+17=7x+3(x-4)-12 equation: 



8x-2(3x-5)+17=7x+3(x-4)-12

We move all terms to the left:

8x-2(3x-5)+17-(7x+3(x-4)-12)=0

We multiply parentheses

8x-6x-(7x+3(x-4)-12)+10+17=0



We calculate terms in parentheses: -(7x+3(x-4)-12), so:

7x+3(x-4)-12

We multiply parentheses

7x+3x-12-12

We add all the numbers together, and all the variables

10x-24

Back to the equation:

-(10x-24)



We add all the numbers together, and all the variables

2x-(10x-24)+27=0

We get rid of parentheses

2x-10x+24+27=0

We add all the numbers together, and all the variables

-8x+51=0

We move all terms containing x to the left, all other terms to the right

-8x=-51

x=-51/-8

x=6+3/8

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