8x-2(3x-1)=3(2-2x)+12

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Solution for 8x-2(3x-1)=3(2-2x)+12 equation: 



8x-2(3x-1)=3(2-2x)+12

We move all terms to the left:

8x-2(3x-1)-(3(2-2x)+12)=0

We add all the numbers together, and all the variables

8x-2(3x-1)-(3(-2x+2)+12)=0

We multiply parentheses

8x-6x-(3(-2x+2)+12)+2=0



We calculate terms in parentheses: -(3(-2x+2)+12), so:

3(-2x+2)+12

We multiply parentheses

-6x+6+12

We add all the numbers together, and all the variables

-6x+18

Back to the equation:

-(-6x+18)



We add all the numbers together, and all the variables

2x-(-6x+18)+2=0

We get rid of parentheses

2x+6x-18+2=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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