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8x-2(3-2x)=3(x-4)-48
We move all terms to the left:
8x-2(3-2x)-(3(x-4)-48)=0
We add all the numbers together, and all the variables
8x-2(-2x+3)-(3(x-4)-48)=0
We multiply parentheses
8x+4x-(3(x-4)-48)-6=0
We calculate terms in parentheses: -(3(x-4)-48), so:We add all the numbers together, and all the variables
3(x-4)-48
We multiply parentheses
3x-12-48
We add all the numbers together, and all the variables
3x-60
Back to the equation:
-(3x-60)
12x-(3x-60)-6=0
We get rid of parentheses
12x-3x+60-6=0
We add all the numbers together, and all the variables
9x+54=0
We move all terms containing x to the left, all other terms to the right
9x=-54
x=-54/9
x=-6
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