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8x-12=4(x-3)+4x
We move all terms to the left:
8x-12-(4(x-3)+4x)=0
We calculate terms in parentheses: -(4(x-3)+4x), so:We get rid of parentheses
4(x-3)+4x
We add all the numbers together, and all the variables
4x+4(x-3)
We multiply parentheses
4x+4x-12
We add all the numbers together, and all the variables
8x-12
Back to the equation:
-(8x-12)
8x-8x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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