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8x-1/4(16x+8)=1/3(9x-12)
We move all terms to the left:
8x-1/4(16x+8)-(1/3(9x-12))=0
Domain of the equation: 4(16x+8)!=0
x∈R
Domain of the equation: 3(9x-12))!=0We calculate fractions
x∈R
8x+(-3x9/(4(16x+8)*3(9x-12)))+(-4x1/(4(16x+8)*3(9x-12)))=0
We calculate terms in parentheses: +(-3x9/(4(16x+8)*3(9x-12))), so:
-3x9/(4(16x+8)*3(9x-12))
We multiply all the terms by the denominator
-3x9
We add all the numbers together, and all the variables
-3x^9
We do not support expression: x^9
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