8x-1-5=8(-2+3x)-2(7x+3)

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Solution for 8x-1-5=8(-2+3x)-2(7x+3) equation: 



8x-1-5=8(-2+3x)-2(7x+3)

We move all terms to the left:

8x-1-5-(8(-2+3x)-2(7x+3))=0

We add all the numbers together, and all the variables

8x-(8(3x-2)-2(7x+3))-1-5=0

We add all the numbers together, and all the variables

8x-(8(3x-2)-2(7x+3))-6=0



We calculate terms in parentheses: -(8(3x-2)-2(7x+3)), so:

8(3x-2)-2(7x+3)

We multiply parentheses

24x-14x-16-6

We add all the numbers together, and all the variables

10x-22

Back to the equation:

-(10x-22)



We get rid of parentheses

8x-10x+22-6=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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