8x-(x-3)=3(x+2)+4x-3

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Solution for 8x-(x-3)=3(x+2)+4x-3 equation: 



8x-(x-3)=3(x+2)+4x-3

We move all terms to the left:

8x-(x-3)-(3(x+2)+4x-3)=0

We get rid of parentheses

8x-x-(3(x+2)+4x-3)+3=0



We calculate terms in parentheses: -(3(x+2)+4x-3), so:

3(x+2)+4x-3

We add all the numbers together, and all the variables

4x+3(x+2)-3

We multiply parentheses

4x+3x+6-3

We add all the numbers together, and all the variables

7x+3

Back to the equation:

-(7x+3)



We add all the numbers together, and all the variables

7x-(7x+3)+3=0

We get rid of parentheses

7x-7x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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