8x+4x-35=2x+80+5x

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Solution for 8x+4x-35=2x+80+5x equation: 



8x+4x-35=2x+80+5x

We move all terms to the left:

8x+4x-35-(2x+80+5x)=0

We add all the numbers together, and all the variables

8x+4x-(7x+80)-35=0

We add all the numbers together, and all the variables

12x-(7x+80)-35=0

We get rid of parentheses

12x-7x-80-35=0

We add all the numbers together, and all the variables

5x-115=0

We move all terms containing x to the left, all other terms to the right

5x=115

x=115/5

x=23

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