8x+4(4x-3)=5(6x+4)-4

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Solution for 8x+4(4x-3)=5(6x+4)-4 equation: 



8x+4(4x-3)=5(6x+4)-4

We move all terms to the left:

8x+4(4x-3)-(5(6x+4)-4)=0

We multiply parentheses

8x+16x-(5(6x+4)-4)-12=0



We calculate terms in parentheses: -(5(6x+4)-4), so:

5(6x+4)-4

We multiply parentheses

30x+20-4

We add all the numbers together, and all the variables

30x+16

Back to the equation:

-(30x+16)



We add all the numbers together, and all the variables

24x-(30x+16)-12=0

We get rid of parentheses

24x-30x-16-12=0

We add all the numbers together, and all the variables

-6x-28=0

We move all terms containing x to the left, all other terms to the right

-6x=28

x=28/-6

x=-4+2/3

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