8x+4(4x-3)=44(6x+4)-4

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Solution for 8x+4(4x-3)=44(6x+4)-4 equation: 



8x+4(4x-3)=44(6x+4)-4

We move all terms to the left:

8x+4(4x-3)-(44(6x+4)-4)=0

We multiply parentheses

8x+16x-(44(6x+4)-4)-12=0



We calculate terms in parentheses: -(44(6x+4)-4), so:

44(6x+4)-4

We multiply parentheses

264x+176-4

We add all the numbers together, and all the variables

264x+172

Back to the equation:

-(264x+172)



We add all the numbers together, and all the variables

24x-(264x+172)-12=0

We get rid of parentheses

24x-264x-172-12=0

We add all the numbers together, and all the variables

-240x-184=0

We move all terms containing x to the left, all other terms to the right

-240x=184

x=184/-240

x=-23/30

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