8x+4(4x-3)=4(x-3)=(6x+4)-4

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Solution for 8x+4(4x-3)=4(x-3)=(6x+4)-4 equation: 



8x+4(4x-3)=4(x-3)=(6x+4)-4

We move all terms to the left:

8x+4(4x-3)-(4(x-3))=0

We multiply parentheses

8x+16x-(4(x-3))-12=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

24x-(4x-12)-12=0

We get rid of parentheses

24x-4x+12-12=0

We add all the numbers together, and all the variables

20x=0

x=0/20

x=0

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