8x+4(4x-3)=4(6x+40-4

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Solution for 8x+4(4x-3)=4(6x+40-4 equation: 



8x+4(4x-3)=4(6x+40-4

We move all terms to the left:

8x+4(4x-3)-(4(6x+40-4)=0

We add all the numbers together, and all the variables

8x+4(4x-3)-(4(6x+36)=0

We multiply parentheses

8x+16x-(4(6x+36)-12=0

We add all the numbers together, and all the variables

24x-(4(6x+36)-12=0

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