8x+4(4x+3)=2(6x-4)-4

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Solution for 8x+4(4x+3)=2(6x-4)-4 equation: 



8x+4(4x+3)=2(6x-4)-4

We move all terms to the left:

8x+4(4x+3)-(2(6x-4)-4)=0

We multiply parentheses

8x+16x-(2(6x-4)-4)+12=0



We calculate terms in parentheses: -(2(6x-4)-4), so:

2(6x-4)-4

We multiply parentheses

12x-8-4

We add all the numbers together, and all the variables

12x-12

Back to the equation:

-(12x-12)



We add all the numbers together, and all the variables

24x-(12x-12)+12=0

We get rid of parentheses

24x-12x+12+12=0

We add all the numbers together, and all the variables

12x+24=0

We move all terms containing x to the left, all other terms to the right

12x=-24

x=-24/12

x=-2

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