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8x+4(3-5)=2-(6x+2)
We move all terms to the left:
8x+4(3-5)-(2-(6x+2))=0
We add all the numbers together, and all the variables
8x-(2-(6x+2))+4(-2)=0
We add all the numbers together, and all the variables
8x-(2-(6x+2))-8=0
We calculate terms in parentheses: -(2-(6x+2)), so:We get rid of parentheses
2-(6x+2)
determiningTheFunctionDomain -(6x+2)+2
We get rid of parentheses
-6x-2+2
We add all the numbers together, and all the variables
-6x
Back to the equation:
-(-6x)
8x+6x-8=0
We add all the numbers together, and all the variables
14x-8=0
We move all terms containing x to the left, all other terms to the right
14x=8
x=8/14
x=4/7
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