8x+3(x-7)=6(1+x)

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Solution for 8x+3(x-7)=6(1+x) equation: 



8x+3(x-7)=6(1+x)

We move all terms to the left:

8x+3(x-7)-(6(1+x))=0

We add all the numbers together, and all the variables

8x+3(x-7)-(6(x+1))=0

We multiply parentheses

8x+3x-(6(x+1))-21=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

11x-(6x+6)-21=0

We get rid of parentheses

11x-6x-6-21=0

We add all the numbers together, and all the variables

5x-27=0

We move all terms containing x to the left, all other terms to the right

5x=27

x=27/5

x=5+2/5

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