8x+3(+5)-5=(x-4)

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Solution for 8x+3(+5)-5=(x-4) equation: 



8x+3(+5)-5=(x-4)

We move all terms to the left:

8x+3(+5)-5-((x-4))=0

We add all the numbers together, and all the variables

8x-((x-4))-5+35=0

We add all the numbers together, and all the variables

8x-((x-4))+30=0



We calculate terms in parentheses: -((x-4)), so:

(x-4)

We get rid of parentheses

x-4

Back to the equation:

-(x-4)



We get rid of parentheses

8x-x+4+30=0

We add all the numbers together, and all the variables

7x+34=0

We move all terms containing x to the left, all other terms to the right

7x=-34

x=-34/7

x=-4+6/7

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