8x+2(10x+-4)=20

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Solution for 8x+2(10x+-4)=20 equation: 



8x+2(10x+-4)=20

We move all terms to the left:

8x+2(10x+-4)-(20)=0

We add all the numbers together, and all the variables

8x+2(10x-4)-20=0

We multiply parentheses

8x+20x-8-20=0

We add all the numbers together, and all the variables

28x-28=0

We move all terms containing x to the left, all other terms to the right

28x=28

x=28/28

x=1

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