8x+1=(3x+17)(3x+18)

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Solution for 8x+1=(3x+17)(3x+18) equation: 



8x+1=(3x+17)(3x+18)

We move all terms to the left:

8x+1-((3x+17)(3x+18))=0

We multiply parentheses ..

-((+9x^2+54x+51x+306))+8x+1=0



We calculate terms in parentheses: -((+9x^2+54x+51x+306)), so:

(+9x^2+54x+51x+306)

We get rid of parentheses

9x^2+54x+51x+306

We add all the numbers together, and all the variables

9x^2+105x+306

Back to the equation:

-(9x^2+105x+306)



We add all the numbers together, and all the variables

8x-(9x^2+105x+306)+1=0

We get rid of parentheses

-9x^2+8x-105x-306+1=0

We add all the numbers together, and all the variables

-9x^2-97x-305=0

a = -9; b = -97; c = -305;
Δ = b2-4ac
Δ = -972-4·(-9)·(-305)
Δ = -1571
Delta is less than zero, so there is no solution for the equation

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