8x+13+x=6(x+4)-5

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Solution for 8x+13+x=6(x+4)-5 equation: 



8x+13+x=6(x+4)-5

We move all terms to the left:

8x+13+x-(6(x+4)-5)=0

We add all the numbers together, and all the variables

9x-(6(x+4)-5)+13=0



We calculate terms in parentheses: -(6(x+4)-5), so:

6(x+4)-5

We multiply parentheses

6x+24-5

We add all the numbers together, and all the variables

6x+19

Back to the equation:

-(6x+19)



We get rid of parentheses

9x-6x-19+13=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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