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8x+1/2(3x+1)=12
We move all terms to the left:
8x+1/2(3x+1)-(12)=0
Domain of the equation: 2(3x+1)!=0We multiply all the terms by the denominator
x∈R
8x*2(3x+1)-12*2(3x+1)+1=0
Wy multiply elements
16x^2(3-24x(3+1=0
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