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8x*8x+4x=12
We move all terms to the left:
8x*8x+4x-(12)=0
We add all the numbers together, and all the variables
4x+8x*8x-12=0
Wy multiply elements
64x^2+4x-12=0
a = 64; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·64·(-12)
Δ = 3088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3088}=\sqrt{16*193}=\sqrt{16}*\sqrt{193}=4\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{193}}{2*64}=\frac{-4-4\sqrt{193}}{128} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{193}}{2*64}=\frac{-4+4\sqrt{193}}{128} $
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