8x(32+5x)=37

Solution for 8x(32+5x)=37 equation:

8x(32+5x)=37

We move all terms to the left:

8x(32+5x)-(37)=0

We add all the numbers together, and all the variables

8x(5x+32)-37=0

We multiply parentheses

40x^2+256x-37=0

a = 40; b = 256; c = -37;
Δ = b2-4ac
Δ = 2562-4·40·(-37)
Δ = 71456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{71456}=\sqrt{16*4466}=\sqrt{16}*\sqrt{4466}=4\sqrt{4466}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(256)-4\sqrt{4466}}{2*40}=\frac{-256-4\sqrt{4466}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(256)+4\sqrt{4466}}{2*40}=\frac{-256+4\sqrt{4466}}{80}
$