8x(2+3x)-2x(3+x)=

Solution for 8x(2+3x)-2x(3+x)= equation:

8x(2+3x)-2x(3+x)=

We move all terms to the left:

8x(2+3x)-2x(3+x)-()=0

We add all the numbers together, and all the variables

8x(3x+2)-2x(x+3)-()=0

We add all the numbers together, and all the variables

8x(3x+2)-2x(x+3)=0

We multiply parentheses

24x^2-2x^2+16x-6x=0

We add all the numbers together, and all the variables

22x^2+10x=0

a = 22; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·22·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*22}=\frac{-20}{44}
=-5/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*22}=\frac{0}{44}
=0
$