8x(2)+17=2x(2)+35

Solution for 8x(2)+17=2x(2)+35 equation:

8x(2)+17=2x(2)+35

We move all terms to the left:

8x(2)+17-(2x(2)+35)=0

We add all the numbers together, and all the variables

-(+2x^2+35)+8x2+17=0

We add all the numbers together, and all the variables

8x^2-(+2x^2+35)+17=0

We get rid of parentheses

8x^2-2x^2-35+17=0

We add all the numbers together, and all the variables

6x^2-18=0

a = 6; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·6·(-18)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*6}=\frac{0-12\sqrt{3}}{12}
=-\frac{12\sqrt{3}}{12}
=-\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*6}=\frac{0+12\sqrt{3}}{12}
=\frac{12\sqrt{3}}{12}
=\sqrt{3}
$