8x^2+16x+10=202

Solution for 8x^2+16x+10=202 equation:

8x^2+16x+10=202

We move all terms to the left:

8x^2+16x+10-(202)=0

We add all the numbers together, and all the variables

8x^2+16x-192=0

a = 8; b = 16; c = -192;
Δ = b2-4ac
Δ = 162-4·8·(-192)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-80}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+80}{2*8}=\frac{64}{16}
=4
$