8t+4(t-1)=12-(8-3t)+1

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Solution for 8t+4(t-1)=12-(8-3t)+1 equation: 



8t+4(t-1)=12-(8-3t)+1

We move all terms to the left:

8t+4(t-1)-(12-(8-3t)+1)=0

We add all the numbers together, and all the variables

8t+4(t-1)-(12-(-3t+8)+1)=0

We multiply parentheses

8t+4t-(12-(-3t+8)+1)-4=0



We calculate terms in parentheses: -(12-(-3t+8)+1), so:

12-(-3t+8)+1

determiningTheFunctionDomain
-(-3t+8)+12+1

We add all the numbers together, and all the variables

-(-3t+8)+13

We get rid of parentheses

3t-8+13

We add all the numbers together, and all the variables

3t+5

Back to the equation:

-(3t+5)



We add all the numbers together, and all the variables

12t-(3t+5)-4=0

We get rid of parentheses

12t-3t-5-4=0

We add all the numbers together, and all the variables

9t-9=0

We move all terms containing t to the left, all other terms to the right

9t=9

t=9/9

t=1

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