8s2+-4s+12=180

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Solution for 8s2+-4s+12=180 equation:



8s^2+-4s+12=180
We move all terms to the left:
8s^2+-4s+12-(180)=0
determiningTheFunctionDomain 8s^2-4s+12-180+=0
We add all the numbers together, and all the variables
8s^2-4s=0
a = 8; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·8·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*8}=\frac{0}{16} =0 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*8}=\frac{8}{16} =1/2 $

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