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8q^2-3q=7q^2-7q-12
We move all terms to the left:
8q^2-3q-(7q^2-7q-12)=0
We get rid of parentheses
8q^2-7q^2-3q+7q+12=0
We add all the numbers together, and all the variables
q^2+4q+12=0
a = 1; b = 4; c = +12;
Δ = b2-4ac
Δ = 42-4·1·12
Δ = -32
Delta is less than zero, so there is no solution for the equation
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