8n-4(n-3)=2(n-1)

Solution for 8n-4(n-3)=2(n-1) equation:

8n-4(n-3)=2(n-1)

We move all terms to the left:

8n-4(n-3)-(2(n-1))=0

We multiply parentheses

8n-4n-(2(n-1))+12=0


We calculate terms in parentheses: -(2(n-1)), so:

2(n-1)

We multiply parentheses

2n-2

Back to the equation:

-(2n-2)


We add all the numbers together, and all the variables

4n-(2n-2)+12=0

We get rid of parentheses

4n-2n+2+12=0

We add all the numbers together, and all the variables

2n+14=0

We move all terms containing n to the left, all other terms to the right

2n=-14

n=-14/2

n=-7