8n-12(n+1)=-6-2(n-2)

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Solution for 8n-12(n+1)=-6-2(n-2) equation: 



8n-12(n+1)=-6-2(n-2)

We move all terms to the left:

8n-12(n+1)-(-6-2(n-2))=0

We multiply parentheses

8n-12n-(-6-2(n-2))-12=0



We calculate terms in parentheses: -(-6-2(n-2)), so:

-6-2(n-2)

determiningTheFunctionDomain
-2(n-2)-6

We multiply parentheses

-2n+4-6

We add all the numbers together, and all the variables

-2n-2

Back to the equation:

-(-2n-2)



We add all the numbers together, and all the variables

-4n-(-2n-2)-12=0

We get rid of parentheses

-4n+2n+2-12=0

We add all the numbers together, and all the variables

-2n-10=0

We move all terms containing n to the left, all other terms to the right

-2n=10

n=10/-2

n=-5

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