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8n(-2n+7)=5
We move all terms to the left:
8n(-2n+7)-(5)=0
We multiply parentheses
-16n^2+56n-5=0
a = -16; b = 56; c = -5;
Δ = b2-4ac
Δ = 562-4·(-16)·(-5)
Δ = 2816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2816}=\sqrt{256*11}=\sqrt{256}*\sqrt{11}=16\sqrt{11}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-16\sqrt{11}}{2*-16}=\frac{-56-16\sqrt{11}}{-32} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+16\sqrt{11}}{2*-16}=\frac{-56+16\sqrt{11}}{-32} $
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