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8m^2+18m+9=0
a = 8; b = 18; c = +9;
Δ = b2-4ac
Δ = 182-4·8·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*8}=\frac{-24}{16} =-1+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*8}=\frac{-12}{16} =-3/4 $
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