8k2-8=-2k

Solution for 8k2-8=-2k equation:

8k^2-8=-2k

We move all terms to the left:

8k^2-8-(-2k)=0

We get rid of parentheses

8k^2+2k-8=0

a = 8; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·8·(-8)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{65}}{2*8}=\frac{-2-2\sqrt{65}}{16}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{65}}{2*8}=\frac{-2+2\sqrt{65}}{16}
$