8k+12=2(k-2)

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Solution for 8k+12=2(k-2) equation: 



8k+12=2(k-2)

We move all terms to the left:

8k+12-(2(k-2))=0



We calculate terms in parentheses: -(2(k-2)), so:

2(k-2)

We multiply parentheses

2k-4

Back to the equation:

-(2k-4)



We get rid of parentheses

8k-2k+4+12=0

We add all the numbers together, and all the variables

6k+16=0

We move all terms containing k to the left, all other terms to the right

6k=-16

k=-16/6

k=-2+2/3

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